Talk:Gnaiger 2018 MiPschool Tromso A2: Difference between revisions

Revision as of 18:27, 14 October 2018

Convert the molar format of the Gibbs force of reaction, Δ_kF_nO2 [kJ/mol], into the electrical format, Δ_kF_eO2 [V].

1. Which physicochemical constant is required? → The Faraday constant, F = e·N_A = 96,485.33 C/mol
2. What is the meaning of the symbol z_O2? → Charge number of O₂ = 4
3. How are the units of electric energy [J] and electric force [V] related? → V = J/C
4. Express -460 kJ/mol O₂ in units of volt [V]. → -460 [kJ/mol]/(4·e·N_A [C/mol]) = -460 [kJ/mol]/(4·96,485.33 [C/mol]) = -0.00119189 kJ/C = -1.2 J/C = -1.2 V
5. Why should we do that? → To relate the driving force of electron transfer to the pmf, we have to express both forces in identical motive units [MU], converting either the force of the chemical reaction from the molar format to the electrical format, or the pmf from the electrical to the molar format.

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 ::::## What is the meaning of the symbol ''z''<sub>O2</sub>? → [[Charge number]] of O<sub>2</sub> = 4
 ::::## How are the units of electric energy [J] and electric force [V] related? → V = J/C
-::::## Express -460 kJ/mol in units of volt [V]. → -460 [kJ/mol]/(4·''e''·''N''<sub>A</sub> [C/mol]) = -460 [kJ/mol]/(4·96,485.33 [C/mol]) = -0.00119189 kJ/C = -1.2 J/C = -1.2 V
+::::## Express -460 kJ/mol O<sub>2</sub> in units of volt [V]. → -460 [kJ/mol]/(4·''e''·''N''<sub>A</sub> [C/mol]) = -460 [kJ/mol]/(4·96,485.33 [C/mol]) = -0.00119189 kJ/C = -1.2 J/C = -1.2 V
 ::::## Why should we do that? → To relate the driving force of electron transfer to the pmf, we have to express both forces in identical [[motive unit]]s [MU], converting either the force of the chemical reaction from the [[molar format]] to the [[electrical format]], or the pmf from the electrical to the molar format.